25 |
|
* Create a queue of given size containing consecutive |
26 |
|
* Integers 0 ... n. |
27 |
|
*/ |
28 |
< |
private ConcurrentLinkedQueue populatedQueue(int n) { |
29 |
< |
ConcurrentLinkedQueue q = new ConcurrentLinkedQueue(); |
28 |
> |
private ConcurrentLinkedQueue<Integer> populatedQueue(int n) { |
29 |
> |
ConcurrentLinkedQueue<Integer> q = new ConcurrentLinkedQueue<Integer>(); |
30 |
|
assertTrue(q.isEmpty()); |
31 |
|
for (int i = 0; i < n; ++i) |
32 |
|
assertTrue(q.offer(new Integer(i))); |
382 |
|
* toArray(a) contains all elements in FIFO order |
383 |
|
*/ |
384 |
|
public void testToArray2() { |
385 |
< |
ConcurrentLinkedQueue q = populatedQueue(SIZE); |
385 |
> |
ConcurrentLinkedQueue<Integer> q = populatedQueue(SIZE); |
386 |
|
Integer[] ints = new Integer[SIZE]; |
387 |
< |
assertSame(ints, q.toArray(ints)); |
387 |
> |
Integer[] array = q.toArray(ints); |
388 |
> |
assertSame(ints, array); |
389 |
|
for (int i = 0; i < ints.length; i++) |
390 |
|
assertSame(ints[i], q.poll()); |
391 |
|
} |