29 |
|
* Create a queue of given size containing consecutive |
30 |
|
* Integers 0 ... n. |
31 |
|
*/ |
32 |
< |
private PriorityQueue populatedQueue(int n) { |
33 |
< |
PriorityQueue q = new PriorityQueue(n); |
32 |
> |
private PriorityQueue<Integer> populatedQueue(int n) { |
33 |
> |
PriorityQueue<Integer> q = new PriorityQueue<Integer>(n); |
34 |
|
assertTrue(q.isEmpty()); |
35 |
|
for (int i = n-1; i >= 0; i-=2) |
36 |
|
assertTrue(q.offer(new Integer(i))); |
415 |
|
* toArray(a) contains all elements |
416 |
|
*/ |
417 |
|
public void testToArray2() { |
418 |
< |
PriorityQueue q = populatedQueue(SIZE); |
418 |
> |
PriorityQueue<Integer> q = populatedQueue(SIZE); |
419 |
|
Integer[] ints = new Integer[SIZE]; |
420 |
< |
assertSame(ints, q.toArray(ints)); |
420 |
> |
Integer[] array = q.toArray(ints); |
421 |
> |
assertSame(ints, array); |
422 |
|
Arrays.sort(ints); |
423 |
|
for (int i = 0; i < ints.length; i++) |
424 |
|
assertSame(ints[i], q.poll()); |